document.write( "Question 132658: Please help.
\n" ); document.write( "1.Solve these using the multiplication principle.
\n" ); document.write( " 9x = 90
\n" ); document.write( " -x = 42
\n" ); document.write( " -x/4 = 11
\n" ); document.write( " -3/5x = 12/35
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Algebra.Com's Answer #96941 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first two to get you started\r
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\n" ); document.write( "\n" ); document.write( "# 1\r
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\n" ); document.write( "\n" ); document.write( "\"9x=90\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2Fcross%289%29%29cross%289%29x=%281%2F%289%29%2990\" Multiply both sides by \"1%2F9\" to isolate x. Note: \"1%2F9\" is the multiplicative inverse of 9\r
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\n" ); document.write( "\n" ); document.write( "\"x=90%2F9\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"x=10\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"x=10\" \r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "\"-x=42\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%28-1%2Fcross%281%29%29cross%28-1%29x=%28-1%2F%281%29%2942\" Multiply both sides by \"-1%2F1\" to isolate x. Note: \"-1%2F1\" is the multiplicative inverse of -1\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-42%29%2F1\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"x=-42\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"x=-42\" \r
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