document.write( "Question 132631: The length of a photograph is 1cm less than twice the width. The area is 23cm squared. Find the dimensions of the photograph. \n" ); document.write( "

Algebra.Com's Answer #96932 by checkley71(8403) $\"\"$ $\"About$

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L=2W-1
\n" ); document.write( "(2W-1)W=23
\n" ); document.write( "2W^2-W-23=0
\n" ); document.write( "USING THE QUADRATIC EQUATION: $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ WE GET:
\n" ); document.write( "W=(1+-SQRT[-1^2-4*2*-23 ])/2*2
\n" ); document.write( "W=(1+-SQRT[1+184])/4
\n" ); document.write( "W=(1+-SQRT185)/4
\n" ); document.write( "W=(1+-13.6)/4
\n" ); document.write( "W=(1+13.6)/4
\n" ); document.write( "W=14.6/4
\n" ); document.write( "W=3.65 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2*3.65-1
\n" ); document.write( "L=7.3-1
\n" ); document.write( "W=6.3 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "3.65*6.3=23
\n" ); document.write( "23=23
\n" ); document.write( " \n" ); document.write( "

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