document.write( "Question 132572:  Suppose that 78% of all Americans support a proposed law to require a police permit before someone is allowed to buy a gun. If a simple random sample of 45 Americans is to be taken, and each person is asked if they support the proposed law, and the sample proportion who do favor such a law is calculated:
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document.write( "a.Specify the sampling distribution of the sample proportion.
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document.write( "b.What is the probability that the sample proportion exceeds 80%?\r
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document.write( "Thanks For any help with this \n" );
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| Algebra.Com's Answer #96914 by stanbon(75887)      You can put this solution on YOUR website! Suppose that 78% of all Americans support a proposed law to require a police permit before someone is allowed to buy a gun. If a simple random sample of 45 Americans is to be taken, and each person is asked if they support the proposed law, and the sample proportion who do favor such a law is calculated: \n" ); document.write( "a.Specify the sampling distribution of the sample proportion. \n" ); document.write( "The mean of the sample-proportions is 0.78 \n" ); document.write( "The standard deviation of the sample-proportions is sqrt[0.78*0.22/45] \n" ); document.write( "------------------------------------ \n" ); document.write( "b.What is the probability that the sample proportion exceeds 80%? \n" ); document.write( "Find the z-score of 0.80 \n" ); document.write( "z(0.80) = (0.80-0.78)/sqrt[0.78*0.22/45] = 0.323875... \n" ); document.write( "P(p-hat >0.80) = P(z>0.323875...) = 0.3730\r \n" ); document.write( "\n" ); document.write( "-------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |