document.write( "Question 132556: Solve.\r
\n" ); document.write( "\n" ); document.write( "sqrt ( 9x + 67 ) = x + 5 \n" ); document.write( "

Algebra.Com's Answer #96891 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
sqrt ( 9x + 67 ) = x + 5 \r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%289x%2B67%29=x%2B5\"$ square both sides--this will get rid of the radical on the left.\r
\n" ); document.write( "\n" ); document.write( " $\"9x%2B67=%28x%2B5%29%5E2\"$ get rid of parens\r
\n" ); document.write( "\n" ); document.write( " $\"9x%2B67=x%5E2%2B10x%2B25\"$ subtract 9x and also 67 from both sides\r
\n" ); document.write( "\n" ); document.write( " $\"9x-9x%2B67-67=x%5E2%2B10x-9x%2B25-67\"$ collect like terms\r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2Bx-42=0\"$ quadratic in standard form and it can be factored\r
\n" ); document.write( "\n" ); document.write( " $\"%28x%2B7%29%28x-6%29=0\"$
\n" ); document.write( " $\"x%2B7=0\"$
\n" ); document.write( " $\"x=-7\"$ ------------------------one solution
\n" ); document.write( " $\"x-6=0\"$
\n" ); document.write( " $\"x=6\"$ -------------------------the other solution\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "substituting x=-7
\n" ); document.write( " $\"sqrt+%284%29=-2\"$
\n" ); document.write( "+ or - 2=-2--- ok\r
\n" ); document.write( "\n" ); document.write( "substituting x=6
\n" ); document.write( " $\"sqrt%28121%29=11\"$
\n" ); document.write( "+ or -11=11---ok\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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