document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20060>Question 20060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> adding cheese to aquarter pounder increases the fat from 23 grams to 32 grams.  What is the percentage of the increase?  I know the answer is 39% but I cannot work it out correctly.  Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9687 by </B><A HREF=/tutors/aboutme.mpl?userid=kunal_122><B>kunal_122(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kunal_122><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first you find the differnce\r<BR>\n" );
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document.write( "that is 32-23=9<BR>\n" );
document.write( "now u divide 23 by and * by 100\r<BR>\n" );
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document.write( "that 23/9*100\r<BR>\n" );
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document.write( "which is 0.391*100\r<BR>\n" );
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document.write( "that is 39.1% or 39% </SPAN>\n" );
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