document.write( "Question 132538: Rita rows 12 km upstream and 12 km downstream in 3 hours. The speed of her boat in still water is 9 km/hr. Find the speed of the stream \n" ); document.write( "
Algebra.Com's Answer #96868 by josmiceli(19441)\"\" \"About 
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The key to these kind of problems is to spot
\n" ); document.write( "the thing that doesn't change in the different
\n" ); document.write( "instances given. In this case it's distance.
\n" ); document.write( "\"d+=+r%2At\"
\n" ); document.write( "(rate going upstream) = (rate of boat in still water - rate of stream)
\n" ); document.write( "(rate going downstream) = (rate of boat in still water + rate of stream)
\n" ); document.write( "The combined time for both trips is \"3\" hours. This is
\n" ); document.write( "separated into \"t\" anf \"3+-+t\"
\n" ); document.write( "\"12+=+%289+%2B+s%29%2At\" (downstream)
\n" ); document.write( "\"12+=+%289+-+s%29%2A%283+-+t%29\" (upstream)
\n" ); document.write( "\"t+=+12+%2F+%289+%2B+s%29\"
\n" ); document.write( "\"12+=+27+-+3s+-+9t+%2B+st\"
\n" ); document.write( "These are 2 equations and 2 unknowns, so should be solvable
\n" ); document.write( "\"12+=+27+-+3s+-+9%2A%2812%2F%289+%2B+s%29%29+%2B+s%2A%2812+%2F+%289+%2B+s%29%29\"
\n" ); document.write( "multiply both sides by \"9+%2B+s\"
\n" ); document.write( "\"12%2A%289+%2B+s%29+=+27%2A%289+%2B+s%29+-+3s%2A%289+%2B+s%29+-+108+%2B+12s\"
\n" ); document.write( "\"108+%2B+12s+=+243+%2B+27s+-+27s+-+3s%5E2+-+108+%2B+12s\"
\n" ); document.write( "\"3s%5E2+%2B+216+-+243+=+0\"
\n" ); document.write( "\"3s%5E2+-+27+=+0\"
\n" ); document.write( "\"3s%5E2+=+27\"
\n" ); document.write( "\"s%5E2+=+9\"
\n" ); document.write( "\"s+=+3\"
\n" ); document.write( "The rate of the stream is 3 km/hr
\n" ); document.write( "check:
\n" ); document.write( "\"12+=+%289+%2B+s%29%2At\" (downstream)
\n" ); document.write( "\"12+=+%289+%2B+3%29%2At\"
\n" ); document.write( "\"12+=+12%2At\"
\n" ); document.write( "\"t+=+1\"
\n" ); document.write( "\"12+=+%289+-+s%29%2A%283+-+t%29\" (upstream)
\n" ); document.write( "\"12+=+%289+-+3%29%2A%283+-+1%29\"
\n" ); document.write( "\"12+=+6%2A2\"
\n" ); document.write( "\"12+=+12\"
\n" ); document.write( "OK
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