document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132511>Question 132511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here's the question:\r<BR>\n" );
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document.write( "If the radius of certain circle is tripled, with 8.2 cm then added, the result is the circumference of the circle. Find the radius of the circle. \r<BR>\n" );
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document.write( "Ok I am assuming part of this is 2(pi)r= r^3 + 8.2 but then I get stuck!! Please help!! Thank you!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96860 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the radius of certain circle is tripled, with 8.2 cm then added, the result is the circumference of the circle. Find the radius of the circle. <BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "3r+8.2 = 2(pi)r<BR>\n" );
document.write( "r(3-2pi) = -8.2<BR>\n" );
document.write( "r = -8.2/(3-2pi)<BR>\n" );
document.write( "r = 2.49757...cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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