document.write( "Question 132505This question is from textbook Holt Algebra 1
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document.write( ": A ship cruising on a river can travel the 135 mile distance between two cities in 15 hours when cruising against the current. When cruising with the current, the trip takes 5 fewer hours. Write and solve a system of equations to find the speed of the current and of the ship in still water. \n" );
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Algebra.Com's Answer #96851 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A ship cruising on a river can travel the 135 mile distance between two cities in 15 hours when cruising against the current. When cruising with the current, the trip takes 5 fewer hours. Write and solve a system of equations to find the speed of the current and of the ship in still water. \n" ); document.write( "------------------------------------ \n" ); document.write( "Upstream DATA: \n" ); document.write( "Distance = 135 miles ; time = 15 hrs. ; rate = 135/15 = 9 mph \n" ); document.write( "------------------- \n" ); document.write( "Downstream DATA: \n" ); document.write( "Distance = 135 miles ; time = 10 hrs. ; rate = 135/10 = 13.5 mph \n" ); document.write( "------------------ \n" ); document.write( "Let current speed be \"c\"; Let boat speed be \"b\". \n" ); document.write( "------------------- \n" ); document.write( "EQUATIONSL \n" ); document.write( "b+c = 13.5 \n" ); document.write( "b-c = 9 \n" ); document.write( "------------ \n" ); document.write( "Add to solve for \"b\": \n" ); document.write( "2b = 22.5 \n" ); document.write( "b = 11.25 mph (boat speed in still water) \n" ); document.write( "----------------- \n" ); document.write( "Substitute to solve for \"c\": \n" ); document.write( "11.25 + c = 13.5 \n" ); document.write( "c = 2.25 mph (current speed) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |