document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132449>Question 132449</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780321443625/algebrahomeworkh>Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A freight train and an express train leave towns 390 km apart, traveling toward one another. The freight train travels 30 km per hour slower than the express train. They pass one another 3 hrs. later. What are their speeds? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96820 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(X-30)+3X=390<BR>\n" );
document.write( "3X-90+3X=390<BR>\n" );
document.write( "6X=390+90<BR>\n" );
document.write( "6X=480<BR>\n" );
document.write( "X=480/6<BR>\n" );
document.write( "X=80 KMH FOR THE EXPRESS TRAIN.<BR>\n" );
document.write( "80-30=50 KMH FOR THE FREIGHT TRAIN.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3*50+3*80=390<BR>\n" );
document.write( "150+240=390<BR>\n" );
document.write( "390=390 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );