document.write( "Question 132410: Okay, I asked this one Friday and nobody got back to me so I am asking it again. Here is the problem...
\n" ); document.write( "Solve the ration expression 5x/3x+1[-]1/9x+3=7/6
\n" ); document.write( "I know all the numerators have to have a LCD and I know how to do that, but once I do that and solve out the problem I am not getting the right answer. If you could help me I would appreciate it!!
\n" ); document.write( "I placed the - sign in [] so you could tell the fraction apart, I am sure you do not need that but I always get confused which fraction is which so I placed it anyways.
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Algebra.Com's Answer #96792 by nycsharkman(136)\"\" \"About 
You can put this solution on YOUR website!
Hello! What you have here is called a fractional equation. The first thing you should do is clear the fractions by, as you said, multiplying every term on both sides of the equation by the LCD.\r
\n" ); document.write( "\n" ); document.write( "Our LCD in this case is: (3x + 1)(9x + 3)(6)\r
\n" ); document.write( "\n" ); document.write( "I will multiply every term on both sides by the LCD.\r
\n" ); document.write( "\n" ); document.write( "5x/(3x + 1) times (3x + 1)(9x + 3)(6) = 5x(9x + 3)(6)\r
\n" ); document.write( "\n" ); document.write( "1/(9x + 3) times (3x + 1)(9x + 3)(6) = -(3x + 1) (6)\r
\n" ); document.write( "\n" ); document.write( "7/6 times (3x + 1)(9x + 3)(6) = 7(3x + 1) (9x + 3)\r
\n" ); document.write( "\n" ); document.write( "Here is what we have now:\r
\n" ); document.write( "\n" ); document.write( "5x(9x + 3)(6)-(3x + 1) (6)= 7(3x + 1) (9x + 3)....Notice that the fractions are gone.\r
\n" ); document.write( "\n" ); document.write( "Can you finish the question now?\r
\n" ); document.write( "\n" ); document.write( "If not, write back.\r
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