document.write( "Question 132411: A rectangle garden has dimensions of 18 feet by 13 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 516 square feet? \n" ); document.write( "
Algebra.Com's Answer #96777 by checkley71(8403)\"\" \"About 
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(18+2X)(13+2X)-18*13=516
\n" ); document.write( "234+26X+36X+4X^2-234=516
\n" ); document.write( "4X^2+62X-516=0
\n" ); document.write( "(2X+43)(2X-12)=0
\n" ); document.write( "2X-12=0
\n" ); document.write( "2X=12
\n" ); document.write( "X=12/2
\n" ); document.write( "X=6 FT. ANSWER FOR THE WIDTH OF THE PATH.
\n" ); document.write( "(18+2*6)(13+2*6)-234=516
\n" ); document.write( "(18+12)(13+12)-234=516
\n" ); document.write( "30*25-234=516
\n" ); document.write( "750-234=516
\n" ); document.write( "516=516
\n" ); document.write( "
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