document.write( "Question 20089: Linear System
\n" ); document.write( "\"2x%2B3y-z=14\"
\n" ); document.write( "\"x-y-z=0\"
\n" ); document.write( "\"3x%2B2y-3z=15\"\r
\n" ); document.write( "\n" ); document.write( "x= y= z=
\n" ); document.write( "

Algebra.Com's Answer #9677 by vidyamanohar(13)\"\" \"About 
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\"2x%2B3y-z=14\"....(i)
\n" ); document.write( "\"x-y-z=0\"...(ii)
\n" ); document.write( "\"3x%2B2y-3z=15\"....(iii)\r
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\n" ); document.write( "\n" ); document.write( "subtracting 3 times (ii) from (iii), we get
\n" ); document.write( "\"5y=15\" which gives \"y=3\"\r
\n" ); document.write( "\n" ); document.write( "subtracting (ii) from (i), we get
\n" ); document.write( "\"x%2B4y=14\"
\n" ); document.write( "and using y=3 we get
\n" ); document.write( "\"x=2\"\r
\n" ); document.write( "\n" ); document.write( "using the values of x and y in (i) we get \"z=-1\"
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