document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132356>Question 132356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive odd integers is 123. Fd the integers.in </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96714 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the smallest of the three odd integer be A. The next integer will be (A+2), and the largest of the three is (A+4)\r<BR>\n" );
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document.write( "Given:  A + (A+2) + (A+4) = 123\r<BR>\n" );
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document.write( "Combine like terms and solve for A as follows<BR>\n" );
document.write( "3A + 6 = 123  <BR>\n" );
document.write( "Subtract 6 from each side of the equation to yield<BR>\n" );
document.write( "3A = 117<BR>\n" );
document.write( "Divide both sides by 3. Yields<BR>\n" );
document.write( "A = 39\r<BR>\n" );
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