document.write( "Question 132308: A girl is now one-fourth as old as her father, and in seven years she will be one-half as old as her father was twelve years ago. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #96684 by checkley71(8403)\"\" \"About 
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LET THE GIRL'S AGE = X & HER FATHER'S AGE = 4X WHICH IS THERE AGES NOW.
\n" ); document.write( "IN 7 YEARS THE GIRL'S AGE WILL BE (X+7).
\n" ); document.write( "IN 7 YEARS THE FATHER'S AGE WILL BE(4X+7).
\n" ); document.write( "(X+7)=(4X-12)/2
\n" ); document.write( "X+7=(4X-12)/2 NOW CROSS MULTIPLY
\n" ); document.write( "2(X+7=4X-12
\n" ); document.write( "2X+14=4X-12
\n" ); document.write( "2X-4X=-12-14
\n" ); document.write( "-2X=-26
\n" ); document.write( "X=-26/-2
\n" ); document.write( "X=13 YEARS OLD FOR THE GIRL NOW.
\n" ); document.write( "4*13=52N AGE OF THE DAD NOW.
\n" ); document.write( "PROOF
\n" ); document.write( "13+7=(4*13-12)/2
\n" ); document.write( "20=(52-12)/2
\n" ); document.write( "20=40/2
\n" ); document.write( "20=20
\n" ); document.write( " \n" ); document.write( "
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