document.write( "Question 20078: The sum of the squares of two consecutive integers is 13. Find the integers and explain your steps as you solve.\r
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Algebra.Com's Answer #9668 by pwac(253)\"\" \"About 
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let x= first number
\n" ); document.write( "so second is x+1
\n" ); document.write( "\"x%5E2+%2B%28x%2B1%29%5E2=13\"multiplying out bracket gives
\n" ); document.write( "\"x%5E2%2Bx%5E2%2B2x%2B1=13\"sum and rearrange
\n" ); document.write( "\"2x%5E2%2B2x-12=0\"divide through by 2
\n" ); document.write( "\"x%5E2%2Bx-6=0\" a quadratic that factors
\n" ); document.write( "(x-2)(x+3)
\n" ); document.write( "x=2
\n" ); document.write( "x=-3
\n" ); document.write( "consecutive numbers are 2 and 3
\n" ); document.write( "the minus sign is irrelevant as -3 squared is same as 3 squared
\n" ); document.write( "Pete
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