document.write( "Question 132297: Can someone please help?\r
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Algebra.Com's Answer #96650 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"3%2Ax%5E2-5%2Ax-7=0\" ( notice \"a=3\", \"b=-5\", and \"c=-7\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28--5+%2B-+sqrt%28+%28-5%29%5E2-4%2A3%2A-7+%29%29%2F%282%2A3%29\" Plug in a=3, b=-5, and c=-7\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%2A3%2A-7+%29%29%2F%282%2A3%29\" Negate -5 to get 5\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25-4%2A3%2A-7+%29%29%2F%282%2A3%29\" Square -5 to get 25 (note: remember when you square -5, you must square the negative as well. This is because \"%28-5%29%5E2=-5%2A-5=25\".)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25%2B84+%29%29%2F%282%2A3%29\" Multiply \"-4%2A-7%2A3\" to get \"84\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+109+%29%29%2F%282%2A3%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28109%29%29%2F6\" Multiply 2 and 3 to get 6\r
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\n" ); document.write( "\n" ); document.write( "Now break up the expression\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B+sqrt%28109%29%29%2F6\" or \"x+=+%285+-+sqrt%28109%29%29%2F6\" \r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=2.57338441815176\" or \"x=-0.906717751485092\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=2.5734\" or \"x=-0.9067\"\r
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\n" ); document.write( "\n" ); document.write( "So that means that the x-intercepts are \r
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\n" ); document.write( "\n" ); document.write( "(-0.9067,0) and (2.5734,0)\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"3%2Ax%5E2-5%2Ax-7\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=2.5734\" and \"x=-0.9067\".So this verifies our answer
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