document.write( "Question 132288: How do I factor by grouping?
\n" ); document.write( "7x^3-28x^2-3x+12
\n" ); document.write( "I started by
\n" ); document.write( "(7x^3-28x^2)+(-3x+12)
\n" ); document.write( "after I did this
\n" ); document.write( "7x(x^2-4x)+-3(x+-4)
\n" ); document.write( "Answer
\n" ); document.write( "(7x-3)(x-4)
\n" ); document.write( "This is not right I don't think I need help! I am not getting it.
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Algebra.Com's Answer #96634 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"7x%5E3-28x%5E2-3x%2B12\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%287x%5E3-28x%5E2%29%2B%28-3x%2B12%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"7x%5E2%28x-4%29-3%28x-4%29\" Factor out the GCF \"7x%5E2\" out of the first group. Factor out the GCF \"-3\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%287x%5E2-3%29%28x-4%29\" Since we have the common term \"x-4\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"7x%5E3-28x%5E2-3x%2B12\" factors to \"%287x%5E2-3%29%28x-4%29\"
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