document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132225>Question 132225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the lab there is a vat of a solution of 20% acid and another vat of solution of 50% acid.  How much of the 50% acid solution should be mixed with the 20% solution to have 12 gallons of a 30% acid solution?\r<BR>\n" );
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document.write( "This was a test question the answer was 4 gallons.\r<BR>\n" );
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document.write( "No matter what I try I can't get this answer.<BR>\n" );
document.write( "I've tried<BR>\n" );
document.write( ".20x+.30(12)=.50(x+12)<BR>\n" );
document.write( ".20x+.50(x+12)=.30(12)<BR>\n" );
document.write( ".30(12) +.50(x-12)=.20x<BR>\n" );
document.write( "(.20x+.50y)/12=30 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96603 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In the lab there is a vat of a solution of 20% acid and another vat of solution of 50% acid. How much of the 50% acid solution should be mixed with the 20% solution to have 12 gallons of a 30% acid solution?<BR>\n" );
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document.write( "50% solution DATA added:<BR>\n" );
document.write( "Amount = \"x\" gallons ; Amt acid is 0.5x gallons <BR>\n" );
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document.write( "20% solution DATA:<BR>\n" );
document.write( "Amount = \"12-x\" gallons; Amt. acid is 0.20(12-x) = 2.4-0.2x gallons<BR>\n" );
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document.write( "30% Mixture DATA:<BR>\n" );
document.write( "Amount = 12 gallons: Amt acid = 0.30*12 = 3.6 gallons<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.5x + 2.4-0.2x = 3.6<BR>\n" );
document.write( "0.3x = 1.2<BR>\n" );
document.write( "x = 4 gallons ( amount of 50% solution in the mixture)<BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.   </SPAN>\n" );
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