document.write( "Question 132205: if y varies directly as to the square of x and inversely as z and y=40 when x=2 and z=1/2. Find y when x=3 and z=9 \n" ); document.write( "
Algebra.Com's Answer #96587 by stanbon(75887)\"\" \"About 
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if y varies directly as to the square of x and inversely as z and y=40 when x=2 and z=1/2. Find y when x=3 and z=9
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\n" ); document.write( "y = kx^2/z
\n" ); document.write( "Find \"k\":
\n" ); document.write( "40 =k(2^2)/(1/2)
\n" ); document.write( "20 = 4k
\n" ); document.write( "k = 5
\n" ); document.write( "EQUATION:
\n" ); document.write( "y = 5x^2/z
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\n" ); document.write( "Find y when x=3 and z=9
\n" ); document.write( "y = 5*(3^2)/9
\n" ); document.write( "y = 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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