document.write( "Question 131868: I have no idea where to start.
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document.write( "Thank You
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document.write( "Find a polynomial for the perimeter and for the area.
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document.write( "a+9 is along the horizontal top of the square and a is on the right vertical side of the square\r
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document.write( "The perimeter is...........
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document.write( "The area is......... \n" );
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Algebra.Com's Answer #96575 by Earlsdon(6294) ![]() You can put this solution on YOUR website! Find a polynomial for the perimeter and for the area of the figure. \n" ); document.write( "The problem says \"square\" but one side (the base) is given as 9+a and another side (the height) is given as a. It can't be a square, so presumably, it's a rectangle whose length (L) is 9a and whose width (W) is a. \n" ); document.write( "The perimeter of a rectangle is: \n" ); document.write( "P = 2L+2W Substitute the given values for L (9a) and for W (a): \n" ); document.write( "P = 2(9a)+2(a) Simplify. \n" ); document.write( "P= 18a+2a This is a polynomial for the perimeter. \n" ); document.write( "The area of a rectangle is: \n" ); document.write( "A = L*W Substitute the given values for L (9a) and for W (a): \n" ); document.write( "A = (9a)(a) Simplify. \n" ); document.write( " |