document.write( "Question 131877: could you tell me if I'm right on this problem?
\n" ); document.write( "(3-i)/ (1+i) = 4+2i I wasn't sure how to solve it,because of the divide sign.
\n" ); document.write( "Thank you for your help in advance,and have a great day! LH
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Algebra.Com's Answer #96574 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Simplify:
\n" ); document.write( "\"%283-i%29%2F%281%2Bi%29\" First, rationalise the denominator by multiplying by its conjugate, \"%281-i%29\"
\n" ); document.write( "\"%283-i%29%281-i%29%2F%281%2Bi%29%281-i%29\" Simplify.
\n" ); document.write( "\"%283-4i%2Bi%5E2%29%2F%281-i%5E2%29\" Substitute:\"i%5E2+=+-1\"
\n" ); document.write( "\"%283-4i%2B%28-1%29%29%2F%281-%28-1%29%29\" Simplify.
\n" ); document.write( "\"%282-4i%29%2F%282%29\" Factor 2 from the numerator.
\n" ); document.write( "\"2%281-2i%29%2F2\" Cancel the 2's to leave you with:
\n" ); document.write( "\"1-2i\", so...
\n" ); document.write( "\"%283-i%29%2F%281%2Bi%29+=+1-2i\"
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