document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20045>Question 20045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to help my 9th grader with algebra and I haven't a clue...She gets confused with the negative/positive part.  When do you change or not: this is the problem:  3(5y+2)=4(3y+2)-1 <BR>\n" );
document.write( "PLEASE help.   thanks dw </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9656 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(5y+2)=4(3y+2)-1 <BR>\n" );
document.write( "First distribute the 3 and the 4;<BR>\n" );
document.write( "15y+6=12y+8-1<BR>\n" );
document.write( "15y+6=12y+7<BR>\n" );
document.write( "Get the variable to one side; so you will subtract the 12y from both sides;<BR>\n" );
document.write( "15y+6-12y=12y+7-12y<BR>\n" );
document.write( "Now you have;<BR>\n" );
document.write( "3y+6=7, now move the 6 to the other side;<BR>\n" );
document.write( "3y+6-6=7-6<BR>\n" );
document.write( "3y=1<BR>\n" );
document.write( "Divide each side by 3;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y%2F3 ALIGN=MIDDLE  ALT=\"3y%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "The rule for when to use negative or positive would;<BR>\n" );
document.write( "You do the OPPOSITE OPERATION!<BR>\n" );
document.write( "So if you have a problem such as;<BR>\n" );
document.write( "7x+3=-4<BR>\n" );
document.write( "you will subtract 3 from both sides because it is being added.<BR>\n" );
document.write( "7x+3-3=-4-3<BR>\n" );
document.write( "In the case of;<BR>\n" );
document.write( "3x-5=16<BR>\n" );
document.write( "You would add 5 to both sides because it is being subtracted.<BR>\n" );
document.write( "3x-5+5=16+5<BR>\n" );
document.write( "That is what I mean by the opposite operation. In the first case the operation was addition; the opposite would be subtraction, in the second case the operation was subtraction so the opposite would be addition!<BR>\n" );
document.write( "Hope you understand!<BR>\n" );
document.write( "If not let me know!<BR>\n" );
document.write( "=)<BR>\n" );
document.write( " </SPAN>\n" );
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