document.write( "Question 131951: Two rainstorms occurred in one week in a certain area. The first storm lasted 25 hours, and the second storm lasted 40 hours, for a total 1600mL of rain. What was the rate of rainfall for each of the two storms if the sum of the two rates was 55 mL per hour? \n" ); document.write( "
Algebra.Com's Answer #96498 by harecurtis(6)![]() ![]() ![]() You can put this solution on YOUR website! Let x=rate of first rainstorm in ml per hour \n" ); document.write( "Total rain from first rainstorm =25*x \n" ); document.write( "Then 55-x=rate of the second rainstorm in ml per hour \n" ); document.write( "Total rain from second rainstorm =40(55-x) \n" ); document.write( "Now we know that the total rainfall (1600 ml) equals total rainfall from first storm (25x) plus total rainfall from second storm (40(55-x)), so our equation to solve is: \n" ); document.write( "25x + 40(55-x)=1600 get rid of parens \n" ); document.write( "25x+2200-40x=1600 subtract 2200 from each side \n" ); document.write( "25x+2200-2200-40x=1600-2200 collect like terms \n" ); document.write( "-15x=-600 divide both sides by -15 \n" ); document.write( "x=40 ml/hr----------------------------------rate of first rainstorm \n" ); document.write( "55-x=55-40=15 ml/hr-------------------------rate of second rainstorm \n" ); document.write( "CK \n" ); document.write( "40*25+15*40=1600 \n" ); document.write( "1000+600=1600 \n" ); document.write( "1600=1600 \n" ); document.write( " |