document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132077>Question 132077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a train station located at some point on a circular track of radius 30/pi miles.  Train A leaves the station at 12:00 traveling 90 mph in the counterclockwise direction.  Two and half hours later train B leaves the same station traveling in the same direction but at 85 mph.  When train A catches B, how many laps has each train done total? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96459 by </B><A HREF=/tutors/aboutme.mpl?userid=kev82><B>kev82(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kev82><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The circumference of the circle is 60, right? Train A goes at 90mph so after 2.5 hours will have done 225 miles. This is 3 and 3/4 times round the circle, right? So at the starting time of train B, train A is 1/4 or 15 miles behind it.\r<BR>\n" );
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document.write( "Train A travels 5 mph faster than B and has to catch up 15 miles, this will take 3 hours.\r<BR>\n" );
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document.write( "So at the time they meet, train A will have gone around for 2.5+3=5.5 hours, at 90mph, which is 495miles, or 8 and 1/4 times. Train B goes round for 3 hours at 85mph, a total of 255 miles which is 4 and 1/4 times round. </SPAN>\n" );
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