document.write( "Question 132038This question is from textbook Holt Algebra 1
\n" ); document.write( ": A coin bank contains nickels, dimes and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank? I figured out the answer but am having a problem with the formula.\r
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Algebra.Com's Answer #96453 by solver91311(24713)\"\" \"About 
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Number of nickels: n
\n" ); document.write( "Number of dimes: d
\n" ); document.write( "Number of quarters: q\r
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\n" ); document.write( "\n" ); document.write( "Value of the nickels: 5n cents
\n" ); document.write( "Value of the dimes: 10d cents
\n" ); document.write( "Value of the quarters: 25q cents\r
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\n" ); document.write( "\n" ); document.write( "Total money: $5.45, but express it as 545 cents.\r
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\n" ); document.write( "\n" ); document.write( "Twice as many quarters as dimes:
\n" ); document.write( "q = 2d or d = q/2\r
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\n" ); document.write( "\n" ); document.write( "11 more nickels than quarters:
\n" ); document.write( "n = q + 11\r
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\n" ); document.write( "\n" ); document.write( "Total value equation:
\n" ); document.write( "5n + 10d + 25q = 545\r
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\n" ); document.write( "\n" ); document.write( "Substitute for n and d
\n" ); document.write( "5(q + 11) + 10(q/2) + 25q = 545\r
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\n" ); document.write( "\n" ); document.write( "You should be able to take it from there.
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