document.write( "Question 132068: The sum of Joe's age and Mary's age is 60 years. Ten years ago, Joe was 3 times as old as Mary was then. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #96447 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! Joe is x years old \n" ); document.write( "Mary is y years old \n" ); document.write( "We are given that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ten years ago, Joe was x - 10 years old and Mary was y - 10 years old. \n" ); document.write( "We are given that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Put the second relationship into standard form ( \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we have two equations in standard form: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply the second equation by -1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the first equation to the second, term by term: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by the coefficient on y: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore Mary is 20 years old now. That means that Joe is 40 years old now (60 - 20). Ten years ago, Joe would have been 30 and Mary would have been 10, and 30 is 3 times 10. Answer checks. \n" ); document.write( " |