document.write( "Question 132066: I need help solving the a word problem. The prefessor was able to give a breaksown of the two equations that will solve the word problem. Can you help me solve these by the substitution method? Thank you!\r
\n" ); document.write( "\n" ); document.write( "1.25x=1.10y=1520
\n" ); document.write( "and
\n" ); document.write( "1.10x+1.25y=1535 \n" ); document.write( "

Algebra.Com's Answer #96433 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
(1) $\"1.25x+%2B+1.1y+=+1520\"$
\n" ); document.write( "(2) $\"1.1x+%2B+1.25y+=+1535\"$
\n" ); document.write( "Notice that in (2), $\"1535+=+1520+%2B+15\"$ , so rewriting,
\n" ); document.write( " $\"1.1x+%2B+1.25y+=+1520+%2B+15\"$
\n" ); document.write( "(3) $\"1.1x+%2B+1.25y+-+15+=+1520\"$
\n" ); document.write( "Set the left side of (1) equal to the left side of (3)
\n" ); document.write( " $\"1.25x+%2B+1.1y+=+1.1x+%2B+1.25y+%2B+15\"$
\n" ); document.write( " $\".15x+-+.15y+=+15\"$
\n" ); document.write( "divide both sides by $\".15\"$
\n" ); document.write( " $\"x+%2B+y+=+100\"$
\n" ); document.write( " $\"y+=+100+-+x\"$
\n" ); document.write( "Substitute this in either equation
\n" ); document.write( " $\"1.25x+%2B+1.1%28100-x%29+=+1520\"$
\n" ); document.write( " $\"1.25x+%2B+110+-+1.1x+=+1520\"$
\n" ); document.write( " $\".15x+=+1410\"$
\n" ); document.write( " $\"x+=+9400\"$ answer
\n" ); document.write( " $\"y+=+100+-+x\"$
\n" ); document.write( " $\"y+=+-9300\"$ answer
\n" ); document.write( "check answers:
\n" ); document.write( "(1) $\"1.25x+%2B+1.1y+=+1520\"$
\n" ); document.write( " $\"1.25%2A9400+%2B+1.1%2A%28-9300%29+=+1520\"$
\n" ); document.write( " $\"11750+-+10230+=+1520\"$
\n" ); document.write( " $\"1520+=+1520\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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