document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132056>Question 132056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Phil can paint the garage in 12 hours and Rick can do it in 10 hours. They work together for 3 hours. How long will it take Rick to finish the job alone? Notice: Although they work for 3 hours, they did not finish the job. Please help me and answer this. If you could explain fully, clearly, and easily, that would be wonderful. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96425 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Phil can paint the garage in 12 hours. That means that each hour he does 1/12 of the job.<BR>\n" );
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document.write( "Rick can paint the garage in 10 hours. That means that each hour he does 1/10 of the garage.<BR>\n" );
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document.write( "If they work together for 3 hours, Phil does 3 times 1/12 of the garage so he does 3/12 or 1/4 of<BR>\n" );
document.write( "the garage or in decimals 0.25 of the garage. <BR>\n" );
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document.write( "At the same time Rick who does 1/10 of the garage every hour does 3/10 of the garage in the<BR>\n" );
document.write( "3 hours and in decimals this is 0.30 of the garage.<BR>\n" );
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document.write( "So in three hours of working together, their combine progress is 0.25 + 0.30 = 0.55<BR>\n" );
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document.write( "This means that of the entire garage they have done 0.55 of it. So there is 0.45 of it left<BR>\n" );
document.write( "(1 - 0.55 = 0.45).<BR>\n" );
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document.write( "At this point Phil quits and Rick presses on by himself. Since he does 1/10 of the garage every<BR>\n" );
document.write( "hour and there are 4.5 tenths of the garage left, it will take Rick 4.5 hours more to <BR>\n" );
document.write( "complete the garage.<BR>\n" );
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document.write( "You can get that from the equation:<BR>\n" );
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document.write( "1/10 * T = 0.45<BR>\n" );
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document.write( "where T represents the time that Rick needs to complete the job after Phil goes on strike.<BR>\n" );
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document.write( "Multiply both sides of this equation by 10 and it becomes:<BR>\n" );
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document.write( "T = 4.5 hours<BR>\n" );
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document.write( "Hope this helps you to understand the problem and enables you to see your way through it in<BR>\n" );
document.write( "a logical fashion.  The whole trick to this method begins by recognizing that if a person can<BR>\n" );
document.write( "do the entire thing by him/herself in x hours, then each hour (s)he does 1/x of the job.<BR>\n" );
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