document.write( "Question 132012: how can i solve \r
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document.write( "logX + logX + 1 = log12 ? \n" );
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Algebra.Com's Answer #96404 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! logX + logX + 1 = log12 \n" ); document.write( "2logX+1=log12 \n" ); document.write( "1=log12-2logx \n" ); document.write( "1=log12-logx^2 \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "By basic definition of logarithms: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since x must be a positive number, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 \n" ); document.write( " \n" ); document.write( " |