document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131997>Question 131997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the standard form of the equation for the parabola having a vertex (-3,6) that contains the origin </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96382 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the standard form of the equation for the parabola having a vertex (-3,6) that contains the origin.<BR>\n" );
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document.write( "Form: y = ax^2+bx+c<BR>\n" );
document.write( "Using (0,0) you find 0 = a*0+b*0+c<BR>\n" );
document.write( "So c = 0<BR>\n" );
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document.write( "Foem y = ax^2+bx<BR>\n" );
document.write( "Using (-3,6) you find 6 = a(-3)^2+b(-3)<BR>\n" );
document.write( "6 = 9a -3b<BR>\n" );
document.write( "2 = 3a-b<BR>\n" );
document.write( "b = 3a-2<BR>\n" );
document.write( "Let a=1, then b = 3*1-2 = 1<BR>\n" );
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document.write( "So a=1,b=1,c=0<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "y = x^2+x<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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