document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131978>Question 131978</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131491040/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I have a problem with factoring.  I don't know how to do it.  I just need to know how to factor this problem then I think I can do the rest.  The directions say solve each inequality algerbraically.\r<BR>\n" );
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document.write( "16.  25x2-40x+16<0\r<BR>\n" );
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document.write( "24.  x3+2x2-3x>0\r<BR>\n" );
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document.write( "Thank you\r<BR>\n" );
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document.write( "Tara </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96380 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25x%5E2-40x%2B16 ALIGN=MIDDLE  ALT=\"25x%5E2-40x%2B16\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Well, if each factor had a 5x and each factor had a -4, that would take care of the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2 ALIGN=MIDDLE  ALT=\"x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and constant terms, so let's see what happens to the middle term:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285x-4%29%285x-4%29=25x%5E2-20x-20x%2B16=25x%5E2-40x%2B16 ALIGN=MIDDLE  ALT=\"%285x-4%29%285x-4%29=25x%5E2-20x-20x%2B16=25x%5E2-40x%2B16\"   DISABLED_style= \"max-width:90%; height:auto;\" >.   Yep, that does it.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E3%2B2x%5E2-3x ALIGN=MIDDLE  ALT=\"x%5E3%2B2x%5E2-3x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This one has at least one x in every term, so you can start by factoring out an x.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28x%5E2%2B2x-3%29 ALIGN=MIDDLE  ALT=\"x%28x%5E2%2B2x-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Now, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A-1=-3 ALIGN=MIDDLE  ALT=\"3%2A-1=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2B%28-1%29=2 ALIGN=MIDDLE  ALT=\"3%2B%28-1%29=2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so the rest of this thing should factor to:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28x-1%29%28x%2B3%29 ALIGN=MIDDLE  ALT=\"x%28x-1%29%28x%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Check by multiplying it out:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28x-1%29%28x%2B3%29=x%28x%5E2%2B3x-x-3%29=x%28x%5E2%2B2x-3%29=x%5E3%2B2x%5E2-3x ALIGN=MIDDLE  ALT=\"x%28x-1%29%28x%2B3%29=x%28x%5E2%2B3x-x-3%29=x%28x%5E2%2B2x-3%29=x%5E3%2B2x%5E2-3x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Yep, that works. </SPAN>\n" );
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