document.write( "Question 131980: I am having a very hard time proving this identity\r
\n" ); document.write( "\n" ); document.write( "sin 2x + sin 4x/cos 2x - cos 4x = cot x. \r
\n" ); document.write( "\n" ); document.write( "If someone could help me that would be great. Also if you could break it down for me and explain what you did I would be very grateful. I have tried doing it several ways and can not figure it out.\r
\n" ); document.write( "\n" ); document.write( "Thanks so much.
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Algebra.Com's Answer #96370 by TakeATuition.com(57)\"\" \"About 
You can put this solution on YOUR website!
SOLUTION -
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\n" ); document.write( " \"%28Sin2x%2Bsin4x%29%2F%28cos2x-cos4x%29\"=cotx
\n" ); document.write( " Taking L.H.S we have
\n" ); document.write( " [\"2sin%28%282x%2B4x%29%2F2%29\"\"cos%28%282x-4x%29%2F2%29\"]/[\"-2sin%28%282x%2B4x%29%2F2%29\"\"sin%28%282x-4x%29%2F2%29\"]
\n" ); document.write( " { (since \"sinc%2Bsind\"=2\"sin%28%28c%2Bd%29%2F2%29\"\"cos%28%28c-d%29%2F2%29\"
\n" ); document.write( " \"cosc-cosd\"=-2\"sin%28%28c%2Bd%29%2F2%29\"\"sin%28%28c-d%29%2F2%29\"}
\n" ); document.write( " =\"%282sin3xcos%28-x%29%29\"/\"%28-2sin3xsin%28-x%29%29\"
\n" ); document.write( " =\"cosx%2Fsinx\" {since cos(-x)=cosx and sin(-x)=-sinx}
\n" ); document.write( " = cotx
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\n" ); document.write( "FOR MORE HELP VISIT :www.TakeATuition.com\r
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