document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131962>Question 131962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the degree measure of an arc whose length is 3Pi and which is part of a circle of radius 12.<BR>\n" );
document.write( "Please Help! Thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96352 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S=r*Theta, where S = Arclength, r=radius, and Theta= angle measured in radians.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3+%2Api=12+Theta ALIGN=MIDDLE  ALT=\"3+%2Api=12+Theta\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide both sides by 12,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Theta+=+pi%2F4=180%2F4=45+degrees ALIGN=MIDDLE  ALT=\"Theta+=+pi%2F4=180%2F4=45+degrees\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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