document.write( "Question 131945: could someone please help me with this problem?
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document.write( "(3-i) / (1+i) I know you use the conjugate and multiply by (3-i) / (1+I) I think,but I don't think I did something right.Thanks for your help in advance.
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document.write( "Sincerely,LH \n" );
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Algebra.Com's Answer #96342 by solver91311(24713) You can put this solution on YOUR website! A conjugate of a complex number \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To simplify an expression with a complex denominator, you need to multiply the entire expression by 1 in the form of the conjugate of the denominator divided by itself. That means if you have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your problem:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The conjugate of the denominator is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now multiply numerator times numerator and denominator times denominator just like multiplying any other pair of fractions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using FOIL, the numerator product becomes: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The denominator product is easier because, by using the conjugate, you have the factors of the difference of two squares, so \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Putting the pieces back together we have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Done.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |