document.write( "Question 131945: could someone please help me with this problem?
\n" ); document.write( "(3-i) / (1+i) I know you use the conjugate and multiply by (3-i) / (1+I) I think,but I don't think I did something right.Thanks for your help in advance.
\n" ); document.write( "Sincerely,LH
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Algebra.Com's Answer #96342 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
A conjugate of a complex number \"a%2Bbi\" is formed by changing the sign on the imaginary part. So the conjugate of \"a%2Bbi\" is \"a-bi\".\r
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\n" ); document.write( "\n" ); document.write( "To simplify an expression with a complex denominator, you need to multiply the entire expression by 1 in the form of the conjugate of the denominator divided by itself. That means if you have \"%28a%2Bbi%29%2F%28c%2Bdi%29\", you want to multiply by 1 in the form of \"%28c-di%29%2F%28c-di%29\".\r
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\n" ); document.write( "\n" ); document.write( "Your problem:\r
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\n" ); document.write( "\n" ); document.write( "\"%283-i%29+%2F+%281%2Bi%29\"\r
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\n" ); document.write( "\n" ); document.write( "The conjugate of the denominator is \"%281-i%29\", so you need to multiply the entire expression by \"%281-i%29%2F%281-i%29\", thus:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%283-i%29%2F%281%2Bi%29%29%28%281-i%29%2F%281-i%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now multiply numerator times numerator and denominator times denominator just like multiplying any other pair of fractions.\r
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\n" ); document.write( "\n" ); document.write( "Using FOIL, the numerator product becomes: \"3%2B3i-i%2B1=4%2B2i\" (remember \"i%5E2=-1\" so \"-i%2Ai=-%28i%5E2%29=-%28-1%29=1\")\r
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\n" ); document.write( "\n" ); document.write( "The denominator product is easier because, by using the conjugate, you have the factors of the difference of two squares, so \"%281%2Bi%29%281-i%29=1-i%5E2=1-%28-1%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "Putting the pieces back together we have \"%284%2B2i%29%2F2=2%2Bi\"\r
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\n" ); document.write( "\n" ); document.write( "Done.\r
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