document.write( "Question 131956: two years ago a father was four times as old as his son. three years from now the father will be only three times as old as the son. How old is each at present? \n" ); document.write( "
Algebra.Com's Answer #96334 by stanbon(75887)\"\" \"About 
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two years ago a father was four times as old as his son. three years from now the father will be only three times as old as the son. How old is each at present?
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\n" ); document.write( "2 years ago DATA:
\n" ); document.write( "Son's age was \"x\"
\n" ); document.write( "Father's age was \"4x\"
\n" ); document.write( "-------------------------
\n" ); document.write( "Three years from now DATA
\n" ); document.write( "Son's age will be \"x+5\"
\n" ); document.write( "Father will be \"4x+5\"
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\n" ); document.write( "EQUATION:
\n" ); document.write( "4x+5 = 3(x+5)
\n" ); document.write( "4x+5 = 3x+15
\n" ); document.write( "x = 10
\n" ); document.write( "Son's age NOW = x+2 = 12 yrs old
\n" ); document.write( "--------------
\n" ); document.write( "Father's age NOW = 4x+2 = 42 yrs old
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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