document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131946>Question 131946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> could someone please help me with this problem? <BR>\n" );
document.write( "(3-i) / (1+i)   I know you use the conjugate and multiply by (3-i) / (1+I) I think,but I don't think I did something right.Thanks for your help in advance.<BR>\n" );
document.write( "Sincerely,LH </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96321 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "OK, YOU ARE ABSOLUTELY RIGHT:  SO LETS USE THE CONJUGATE AND WHAT THIS WILL DO IS GET RID OF THE RADICAL IN THE DENOMINATOR (AS YOU KNOW, THE CONJUGATE OF 1+i IS 1-i.\r<BR>\n" );
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document.write( "((3-i)(1-i))/(1+i)(1-i)) <BR>\n" );
document.write( "The numerator reduces to(using FOIL: First, Outer, Inner, Last):\r<BR>\n" );
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document.write( "3-3i-i+i^2 (i^2=-1) so we have for the numerator:\r<BR>\n" );
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document.write( "3-4i-1=2-4i<BR>\n" );
document.write( "For the denominator we have:\r<BR>\n" );
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document.write( "1-i+i-i^2; (-(i^2))=(-(-1))=+1 so we have\r<BR>\n" );
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document.write( "1+1=2 \r<BR>\n" );
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document.write( "Putting the numerator and denominator back together, we have:<BR>\n" );
document.write( "(2-4i)/2  divide numerator and denominator by 2 we get:\r<BR>\n" );
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document.write( "1-2i-------------------ans\r<BR>\n" );
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document.write( "Hope this helps----ptaylor<BR>\n" );
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