document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131853>Question 131853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this.\r<BR>\n" );
document.write( "\n" );
document.write( "Anne has two solutions, one with 6% iron and one with 2% iron. How many liters of each solution should be mixed to create 16 liters of a solution with 3% iron content? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96291 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .06X+.02(16-X)=.03*16<BR>\n" );
document.write( ".06X+.32-.02X=.48<BR>\n" );
document.write( ".04X=.48-.32<BR>\n" );
document.write( ".04X=.16<BR>\n" );
document.write( "X=.16/.04<BR>\n" );
document.write( "X=4 LITERS OF 6% IRON IS NEEDED.<BR>\n" );
document.write( "14-4=10 LITERS OF 2% IRON IS NEEDED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".06*4+.02*10=.48<BR>\n" );
document.write( ".24+20=.48<BR>\n" );
document.write( ".48=.48 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );