document.write( "Question 131835: How do you solve this so I can understand f(x)=-2x^2+2x+6 \n" ); document.write( "
Algebra.Com's Answer #96256 by edjones(8007)![]() ![]() You can put this solution on YOUR website! f(x)=-2x^2+2x+6 \n" ); document.write( "-2(x^2-x-3) \n" ); document.write( "To find the zeroes: \n" ); document.write( "x^2-x-3=0 \n" ); document.write( "x^2-x =3 \n" ); document.write( "x^2-x+ 1/4=3+ 1/4 complete the square by taking 1/2 the middle term and squaring it. \n" ); document.write( "(x- 1/2)^2=13/4 \n" ); document.write( "x- 1/2=+-sqrt(13)/2 sqrt of each side. \n" ); document.write( "x=1/2+-sqrt(13)/2 \n" ); document.write( "x=(1+sqrt(13))/2, (1-sqrt(13))/2 \n" ); document.write( ". \n" ); document.write( "The 2 places the graph crosses the x axis (the x intercepts[where y=0]) also give the answer. \n" ); document.write( "You could also use the quadratic equation. \n" ); document.write( "Ed \n" ); document.write( " |