document.write( "Question 131835: How do you solve this so I can understand f(x)=-2x^2+2x+6 \n" ); document.write( "
Algebra.Com's Answer #96256 by edjones(8007)\"\" \"About 
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f(x)=-2x^2+2x+6
\n" ); document.write( "-2(x^2-x-3)
\n" ); document.write( "To find the zeroes:
\n" ); document.write( "x^2-x-3=0
\n" ); document.write( "x^2-x =3
\n" ); document.write( "x^2-x+ 1/4=3+ 1/4 complete the square by taking 1/2 the middle term and squaring it.
\n" ); document.write( "(x- 1/2)^2=13/4
\n" ); document.write( "x- 1/2=+-sqrt(13)/2 sqrt of each side.
\n" ); document.write( "x=1/2+-sqrt(13)/2
\n" ); document.write( "x=(1+sqrt(13))/2, (1-sqrt(13))/2
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\n" ); document.write( "The 2 places the graph crosses the x axis (the x intercepts[where y=0]) also give the answer.
\n" ); document.write( "You could also use the quadratic equation.
\n" ); document.write( "Ed
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