document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=131837>Question 131837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely:<BR>\n" );
document.write( "x^3 – 2x^2 + 6x – 12\r<BR>\n" );
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document.write( ".  Factor completely:<BR>\n" );
document.write( "x^2 + 17x + 16\r<BR>\n" );
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document.write( "Factor completely:<BR>\n" );
document.write( "8x^2 + 6x – 5<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96250 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^3 – 2x^2 + 6x – 12<BR>\n" );
document.write( "x^2(x-2)+6(x-2) Factoring by grouping.<BR>\n" );
document.write( "(x^2+6)(x-2)<BR>\n" );
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document.write( "x^2 + 17x + 16<BR>\n" );
document.write( "(x+16)(x+1)<BR>\n" );
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document.write( "8x^2 + 6x – 5<BR>\n" );
document.write( "8*-5=-40<BR>\n" );
document.write( "What 2 factors -40 when added equal +6? Ans: 10, -4<BR>\n" );
document.write( "8x^2+10x-4x-5 Put -4x and 10xin the middle in either order.<BR>\n" );
document.write( "2x(4x+5)-(4x-5) Factoring by grouping again.<BR>\n" );
document.write( "(2x-1)(4x+5)<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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