document.write( "Question 131831: I have six more than twice as many dimes as I have nickels. I have four less quarters than nickels. Altogether I have $5.60. How many of each coin do I have? \n" ); document.write( "
Algebra.Com's Answer #96248 by stanbon(75887)\"\" \"About 
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I have six more than twice as many dimes as I have nickels. I have four less quarters than nickels. Altogether I have $5.60. How many of each coin do I have?
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\n" ); document.write( "Let number of nickels be \"x\" ; value of these is 5x cents
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\n" ); document.write( "# of dimes = \"2x+6\" ; value is 10(2x+6) = 20x+60 cents
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\n" ); document.write( "# of quarters = \"x-4\" ;value is 25(x-4) = 25x-100 cents
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\n" ); document.write( "EQUATION:
\n" ); document.write( "value + value + value = 560cents
\n" ); document.write( "5x + 20x+60 + 25x-100 = 560
\n" ); document.write( "50x = 600
\n" ); document.write( "x = 12 (# of nickels)
\n" ); document.write( "2x+6 = 32 (# of dimes)
\n" ); document.write( "x-4 = 8 (# of quarters)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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