document.write( "Question 131783: Find and label the vertex and the line of symmetry. Graph the function.\r
\n" ); document.write( "\n" ); document.write( "f(x) = 1/4x^2\r
\n" ); document.write( "\n" ); document.write( "I tried using the solver and nothing computed, but this is the whole problem. I'm stuck.
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Algebra.Com's Answer #96205 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I presume you mean that \"f%28x%29=%281%2F4%29x%5E2\" as opposed to \"f%28x%29=1%2F%284x%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Given that assumption, you can re-write your equation as:\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%281%2F4%29x%5E2%2B0x%2B0\" to put it in the \"ax%5E2%2Bbx%2Bc\" form, with a = 1/4, b = 0, and c = 0.\r
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\n" ); document.write( "\n" ); document.write( "Now recall that the x-coordinate of the parabola vertex is \"-b%2F2a\". In this case: \"-0%2F%282%281%2F4%29%29=0\".\r
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\n" ); document.write( "\n" ); document.write( "And the y-coordinate of the vertex is at \"f%280%29=%281%2F4%290%5E2%2B0%2A0%2B0=0\".\r
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\n" ); document.write( "\n" ); document.write( "Now we know that the vertex is at (0,0).\r
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\n" ); document.write( "\n" ); document.write( "We know that the axis of symmetry is a vertical line that intersects the vertex, so the equation of the axis is \"x=0\"\r
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