document.write( "Question 131749: Please help me solve this word problem:\r
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document.write( "Chip and Layla found a hole in the fence and decided to make a run for it at the same time. Chip headed north trotting at x miles per hour. Layla ran east, running 2 miles an hour faster than Chip. In 2 hours, they were 20 miles apart (as the crow flies- think hypotenuse). How fast was each dog going? \n" );
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Algebra.Com's Answer #96183 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! C: x mph \n" ); document.write( "L: x + 2 mph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the distance Chip ran was 2x (2 hours at x miles per hour), the distance Layla ran was 2(x + 2) (2 hours at x + 2 miles per hour). Since their directions of travel were 90 degrees apart, the square of Chip's distance plus the square of Layla's distance equals the square of the straight line distance between the two.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the quadratic formula on this beast.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So Chip was going \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Of course, I don't believe it for a minute. Some breeds of dog can manage 42 mph in a short sprint, but I would be surprised to learn that there is a breed that can sustain 15 or even 13 mph for 2 hours. \n" ); document.write( " |