document.write( "Question 131707: log 2 + log x = log 3 \r
\n" ); document.write( "\n" ); document.write( "log 2 + log x = 3\r
\n" ); document.write( "\n" ); document.write( "I'm so confused, how do I solve these?\r
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Algebra.Com's Answer #96175 by rapaljer(4671)\"\" \"About 
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log 2 + log x = 3\r
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\n" ); document.write( "\n" ); document.write( "By the first law of logarithms:
\n" ); document.write( "log 2x=3\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C2x%29=3+\"
\n" ); document.write( "\"10%5E3=2x\"
\n" ); document.write( "\"1000=2x\"
\n" ); document.write( "\"500=x\"\r
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\n" ); document.write( "\n" ); document.write( "R^2
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