document.write( "Question 131732: n-n/3=1/2 Solve for n
\n" ); document.write( "this is not from a textbook. This from a handout from the teacher.
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Algebra.Com's Answer #96169 by solver91311(24713)\"\" \"About 
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\"n-n%2F3=1%2F2\" is equivalent to:\r
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\n" ); document.write( "\n" ); document.write( "\"n%2F1-n%2F3=1%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "You need a lowest common denominator for the three fractions, and between denominators of 1, 2, and 3, all of which are either 1 or prime, the LCD is the product of the three, \"1%2A2%2A3=6\", so:\r
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\n" ); document.write( "\n" ); document.write( "\"%286%2F6%29%28n%2F1%29-%282%2F2%29%28n%2F3%29=%283%2F3%29%281%2F2%29\", which is equivalent to your original equation because I multiplied each of the terms by 1. \"6%2F6=2%2F2=3%2F3=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"6n%2F6-2n%2F6=3%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "Now multiply by 6:
\n" ); document.write( "\"6n-2n=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"4n=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"n=3%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Check the answer:\r
\n" ); document.write( "\n" ); document.write( "\"n-n%2F3=1%2F2\"
\n" ); document.write( "\"%283%2F4%29-%283%2F4%29%2F3=1%2F2\"
\n" ); document.write( "\"%283%2F4%29-%283%2F4%29%281%2F3%29=1%2F2\"
\n" ); document.write( "\"%283%2F4%29-%281%2F4%29=2%2F4=1%2F2\" Answer checks
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