document.write( "Question 131657: Please help me solve for x. I'm having trouble with the radical.\r
\n" ); document.write( "\n" ); document.write( "f(x)= 3x+3 sq rt x-6 \n" ); document.write( "

Algebra.Com's Answer #96116 by TakeATuition.com(57) $\"\"$ $\"About$

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SOLUTION -
\n" ); document.write( " f(x) = $\"3x%2B3sqrt%28x%29-6\"$
\n" ); document.write( " taking $\"sqrt+%28x%29=y\"$
\n" ); document.write( " therefore $\"x=y%5E2\"$
\n" ); document.write( "we have
\n" ); document.write( " $\"3y%5E2%2B3y-6\"$
\n" ); document.write( " $\"3y%5E2%2B6y-3y-6\"$
\n" ); document.write( " $\"3y%28y%2B2%29-3%28y%2B2%29\"$
\n" ); document.write( " $\"%28y%2B2%29%283y-3%29\"$
\n" ); document.write( " $\"y%2B2=0\"$
\n" ); document.write( " $\"y=-2\"$
\n" ); document.write( " $\"3y-3=0\"$
\n" ); document.write( " $\"3y=3\"$
\n" ); document.write( " $\"y=1\"$ \r
\n" ); document.write( "\n" ); document.write( "now $\"sqrt+%28x%29=y\"$
\n" ); document.write( "substituting the value of y we have
\n" ); document.write( " when y=-2
\n" ); document.write( " $\"sqrt+%28x%29=-2\"$
\n" ); document.write( " $\"x=%28-2%29%5E2\"$
\n" ); document.write( " $\"x=4\"$
\n" ); document.write( " when y=1
\n" ); document.write( " $\"sqrt+%28x%29=1\"$
\n" ); document.write( " $\"x=1%5E2\"$
\n" ); document.write( " x=1\r
\n" ); document.write( "\n" ); document.write( "FOR MORE HELP VISIT : www.TakeATuition.com\r
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