document.write( "Question 131609: I have to factor this problem and I have not found a solution for it.
\n" ); document.write( "8ksquared-19k+9 \n" ); document.write( "
Algebra.Com's Answer #96085 by 067isa(13)\"\" \"About 
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8k^2-19k+9 the AC is good way to do factoring
\n" ); document.write( "Ac= 8*9 = 72
\n" ); document.write( "so now we looking for two numbers the product of the is 72 and the sum is 19
\n" ); document.write( " factor out the 72 starting with one
\n" ); document.write( "72= 1.72 sum 73
\n" ); document.write( " 2.36 38
\n" ); document.write( " 3.24 27
\n" ); document.write( " 4.18 22
\n" ); document.write( " 6.12 18
\n" ); document.write( " 8.9 17
\n" ); document.write( " not by AC method USe Quadritic formula this equation to double check
\n" ); document.write( "D= B^2-4AC = (19)^2-4(72)= 361 -288 = 73\r
\n" ); document.write( "\n" ); document.write( "x= (-b +- sqrt( b^2-4*a*c ))/(2*a)
\n" ); document.write( "x= -(-19)+-sqrt(73)/ 2(8)= 19 +sqrt(73)/ 16 and 19 - sqrt(73)/ 16 that it \r
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