document.write( "Question 131572: April, Mae, june and Julie were born in consecutive years, in that order, with april being the oldest. All they will tell you is that the sum of the squares of their ages is 534. How old are they? \n" ); document.write( "

Algebra.Com's Answer #96054 by Edwin McCravy(20056) $\"\"$ $\"About$

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April, Mae, June and Julie were born in consecutive years, in that order, with april being the oldest. All they will tell you is that the sum of the squares of their ages is 534. How old are they?
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document.write( " Let Julie's age = X\r\n" );
document.write( " then June's age = X+1\r\n" );
document.write( "   and Mae's age = X+2\r\n" );
document.write( " and April's age = X+3\r\n" );
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document.write( "                   X² + (X + 1)² + (X + 2)² + (X + 3)² = 534\r\n" );
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document.write( "X² +  (X + 1)(X + 1) + (X + 2)(X + 2) + (X + 3)(X + 3) = 534\r\n" );
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document.write( "    X² + (X² + 2X + 1) + (X² + 4X + 4) + (X² + 6X + 9) = 534  \r\n" );
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document.write( "          X² + X² + 2X + 1 + X² + 4X + 4 + X² + 6X + 9 = 534\r\n" );
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document.write( "                                        4X² + 12X + 14 = 534\r\n" );
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document.write( "                                       4X² + 12X - 520 = 0  \r\n" );
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document.write( "Divide every term by 4\r\n" );
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document.write( "                                         X² + 3X - 130 = 0\r\n" );
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document.write( "                                      (X + 13)(X - 10) = 0\r\n" );
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document.write( "                                      Solutions are -13 and 10.\r\n" );
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document.write( "Discard the negative answer.  So \r\n" );
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document.write( "X = 10 = Julie's age, so\r\n" );
document.write( "Julie's age = X = 10\r\n" );
document.write( "June's age = X+1 = 10+1 = 11\r\n" );
document.write( "Mae's age = X+2 = 10+2 = 12\r\n" );
document.write( "April's age = X+3 = 10+3 = 13\r\n" );
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document.write( "Edwin

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