document.write( "Question 131565: Olivia, Newt, and John were each born 3 years apart, with Olivia the youngest and john the oldest. The sum of the squares of their ages is 606. How old is each? \n" ); document.write( "
Algebra.Com's Answer #96038 by stanbon(75887)\"\" \"About 
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Olivia, Newt, and John were each born 3 years apart, with Olivia the youngest and john the oldest. The sum of the squares of their ages is 606. How old is each?
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\n" ); document.write( "Let Olivia's age be \"x\"
\n" ); document.write( "Newt's age is \"x+3\"
\n" ); document.write( "John's age is \"x+6\"
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\n" ); document.write( "EQUATION
\n" ); document.write( "x^2 + (x+3)^2 + (x+6)^2 = 606
\n" ); document.write( "x^2 + x^+6x+9 + x^2+12x+36 = 606
\n" ); document.write( "3x^2 + 18x + 45 = 606
\n" ); document.write( "x^2 + 6x - 187 = -
\n" ); document.write( "(x-11)(x+17)=0
\n" ); document.write( "Positive Solution:
\n" ); document.write( "x = 11 (Olivia's age)
\n" ); document.write( "x+3 = 14 (Newt's age)
\n" ); document.write( "x+6 = 17 (John's age)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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