document.write( "Question 131555: Hi the chapter im on is called Exponential and Logarithmic functions. I had a question on a word problem from it.\r
\n" ); document.write( "\n" ); document.write( "Here it is:
\n" ); document.write( "The voltage input of an amplifier is 0.5 volts. Its voltage output is 52 volts. Use the formula d=10log(E base 0/E base 1), where d is the decibel voltage, E base 0 is the output voltage, and E base 1 is the input voltage to find the decibel voltage.\r
\n" ); document.write( "\n" ); document.write( "Okay this question makes no sense to me so if someone can figure it out.. Thank u! \n" ); document.write( "
Algebra.Com's Answer #96030 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The voltage input of an amplifier is 0.5 volts. Its voltage output is 52 volts. Use the formula d=10log(E base 0/E base 1), where d is the decibel voltage, E base 0 is the output voltage, and E base 1 is the input voltage to find the decibel voltage.
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\n" ); document.write( "d=10log(E base 0/E base 1)
\n" ); document.write( "Substitute the values you are given to get:
\n" ); document.write( "d = 10log(52/1)
\n" ); document.write( "d = 10*1.716...
\n" ); document.write( "d = 17.16 db
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\n" ); document.write( "O is like the output of a loudspeaker
\n" ); document.write( "E is like the voice of a person singing
\n" ); document.write( "17.16 is the gain in power produced by the amplifier.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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