document.write( "Question 131554: Find two consecutive odd integers such that seven times the first equals five times the second. \n" ); document.write( "

Algebra.Com's Answer #96027 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
If an odd integer is x, then the next consecutive odd integer must be x + 2 (that's because x + 1 would be an even integer).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We are told that seven times the first [7x] is equal to five times the second [5(x + 2)].\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"7x=5%28x%2B2%29\"$
\n" ); document.write( " $\"7x=5x%2B10\"$
\n" ); document.write( " $\"7x-5x=10\"$
\n" ); document.write( " $\"2x=10\"$
\n" ); document.write( " $\"x=5\"$ \r
\n" ); document.write( "\n" ); document.write( "So the first odd integer is 5 and the next consecutive one is 5 + 2 = 7, and by the way, 7 times 5 = 5 times 7, so the answer checks. \n" ); document.write( "

\n" );